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1856 United States presidential election in Delaware

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1856 United States presidential election in Delaware

← 1852 November 4, 1856 1860 →
 
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew Jackson Donelson
Electoral vote 3 0
Popular vote 8,004 6,275
Percentage 54.83% 42.99%

County Results
Buchanan
  50-60%


President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

The 1856 United States presidential election in Delaware took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Delaware voted for the Democratic candidate, James Buchanan, over the Republican candidate, John C. Frémont, and the Know Nothing candidate, Millard Fillmore.

Buchanan won the state by a margin of 11.84%.

Results

[edit]
1856 United States presidential election in Delaware[1]
Party Candidate Votes %
Democratic James Buchanan 8,004 54.83%
Know Nothing Millard Fillmore 6,275 42.99%
Republican John C. Fremont 310 2.12%
Others 9 0.06%
Total votes 14,598 100%

Results By County

[edit]
1856 United States Presidential Election in Delaware (By County)[2][3]
County James Buchanan

Democratic

Millard Fillmore

Know Nothing

John C. Frémont

Republican

Total Votes Cast
# % # % # %
Kent 2,083 57.65% 1,530 42.35% 0 0.00% 3,613
New Castle 3,576 54.96% 2,625 40.34% 306 4.70% 6,507
Sussex 2,344 53.71% 2,020 46.29% 0 0.00% 4,364
Total 8,003 55.25% 6,175 42.63% 306 2.11% 14,484

See also

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References

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  1. ^ "1856 Presidential General Election Results - Delaware".
  2. ^ The Tribune Almanac and Political Register. Tribune Association. 1861.
  3. ^ Dubin, Michael J. United States Presidential Elections. 1788-1870: The Official Results by County and State. ISBN 978-0-7864-6422-7.